Integrand size = 25, antiderivative size = 664 \[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\frac {5 b^{3/2} \left (7 a^2-2 b^2\right ) \arctan \left (\frac {\sqrt {b} \sqrt [4]{\sec ^2(e+f x)}}{\sqrt [4]{a^2+b^2}}\right ) \sqrt [4]{\sec ^2(e+f x)}}{8 \left (a^2+b^2\right )^{13/4} f \sqrt {d \sec (e+f x)}}-\frac {5 b^{3/2} \left (7 a^2-2 b^2\right ) \text {arctanh}\left (\frac {\sqrt {b} \sqrt [4]{\sec ^2(e+f x)}}{\sqrt [4]{a^2+b^2}}\right ) \sqrt [4]{\sec ^2(e+f x)}}{8 \left (a^2+b^2\right )^{13/4} f \sqrt {d \sec (e+f x)}}+\frac {a \left (8 a^2-37 b^2\right ) E\left (\left .\frac {1}{2} \arctan (\tan (e+f x))\right |2\right ) \sqrt [4]{\sec ^2(e+f x)}}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \operatorname {EllipticPi}\left (-\frac {b}{\sqrt {a^2+b^2}},\arcsin \left (\sqrt [4]{\sec ^2(e+f x)}\right ),-1\right ) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}}{8 \left (a^2+b^2\right )^{7/2} f \sqrt {d \sec (e+f x)}}+\frac {5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \operatorname {EllipticPi}\left (\frac {b}{\sqrt {a^2+b^2}},\arcsin \left (\sqrt [4]{\sec ^2(e+f x)}\right ),-1\right ) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}}{8 \left (a^2+b^2\right )^{7/2} f \sqrt {d \sec (e+f x)}}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))} \]
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Time = 1.09 (sec) , antiderivative size = 664, normalized size of antiderivative = 1.00, number of steps used = 19, number of rules used = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.640, Rules used = {3593, 755, 849, 858, 233, 202, 760, 408, 504, 1227, 551, 455, 65, 304, 211, 214} \[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=-\frac {5 a b \left (7 a^2-2 b^2\right ) \sqrt {-\tan ^2(e+f x)} \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \operatorname {EllipticPi}\left (-\frac {b}{\sqrt {a^2+b^2}},\arcsin \left (\sqrt [4]{\sec ^2(e+f x)}\right ),-1\right )}{8 f \left (a^2+b^2\right )^{7/2} \sqrt {d \sec (e+f x)}}+\frac {5 a b \left (7 a^2-2 b^2\right ) \sqrt {-\tan ^2(e+f x)} \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \operatorname {EllipticPi}\left (\frac {b}{\sqrt {a^2+b^2}},\arcsin \left (\sqrt [4]{\sec ^2(e+f x)}\right ),-1\right )}{8 f \left (a^2+b^2\right )^{7/2} \sqrt {d \sec (e+f x)}}+\frac {a \left (8 a^2-37 b^2\right ) \sqrt [4]{\sec ^2(e+f x)} E\left (\left .\frac {1}{2} \arctan (\tan (e+f x))\right |2\right )}{4 f \left (a^2+b^2\right )^3 \sqrt {d \sec (e+f x)}}+\frac {5 b^{3/2} \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)} \arctan \left (\frac {\sqrt {b} \sqrt [4]{\sec ^2(e+f x)}}{\sqrt [4]{a^2+b^2}}\right )}{8 f \left (a^2+b^2\right )^{13/4} \sqrt {d \sec (e+f x)}}-\frac {5 b^{3/2} \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)} \text {arctanh}\left (\frac {\sqrt {b} \sqrt [4]{\sec ^2(e+f x)}}{\sqrt [4]{a^2+b^2}}\right )}{8 f \left (a^2+b^2\right )^{13/4} \sqrt {d \sec (e+f x)}}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 f \left (a^2+b^2\right )^3 \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 f \left (a^2+b^2\right )^2 \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}-\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 f \left (a^2+b^2\right )^3 \sqrt {d \sec (e+f x)}}+\frac {2 (a \tan (e+f x)+b)}{f \left (a^2+b^2\right ) \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2} \]
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Rule 65
Rule 202
Rule 211
Rule 214
Rule 233
Rule 304
Rule 408
Rule 455
Rule 504
Rule 551
Rule 755
Rule 760
Rule 849
Rule 858
Rule 1227
Rule 3593
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt [4]{\sec ^2(e+f x)} \text {Subst}\left (\int \frac {1}{(a+x)^3 \left (1+\frac {x^2}{b^2}\right )^{5/4}} \, dx,x,b \tan (e+f x)\right )}{b f \sqrt {d \sec (e+f x)}} \\ & = \frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}-\frac {\left (2 b \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {\frac {1}{2} \left (-5+\frac {a^2}{b^2}\right )-\frac {3 a x}{2 b^2}}{(a+x)^3 \sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)}} \\ & = \frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {\left (b^3 \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {-\frac {a \left (a^2-8 b^2\right )}{b^4}+\frac {\left (4 a^2-5 b^2\right ) x}{4 b^4}}{(a+x)^2 \sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{\left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)}} \\ & = \frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}-\frac {\left (b^5 \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {\frac {1}{4} \left (\frac {4 a^4}{b^6}-\frac {36 a^2}{b^4}+\frac {5}{b^2}\right )+\frac {a \left (8 a^2-37 b^2\right ) x}{8 b^6}}{(a+x) \sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{\left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}} \\ & = \frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}-\frac {\left (a \left (8 a^2-37 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{8 b \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {\left (5 b \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{(a+x) \sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}} \\ & = -\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}+\frac {\left (a \left (8 a^2-37 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {x^2}{b^2}\right )^{5/4}} \, dx,x,b \tan (e+f x)\right )}{8 b \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {\left (5 b \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {x}{\left (a^2-x^2\right ) \sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {\left (5 a b \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (a^2-x^2\right ) \sqrt [4]{1+\frac {x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}} \\ & = \frac {a \left (8 a^2-37 b^2\right ) E\left (\left .\frac {1}{2} \arctan (\tan (e+f x))\right |2\right ) \sqrt [4]{\sec ^2(e+f x)}}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}-\frac {\left (5 b \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (a^2-x\right ) \sqrt [4]{1+\frac {x}{b^2}}} \, dx,x,b^2 \tan ^2(e+f x)\right )}{16 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {\left (5 a \left (7 a^2-2 b^2\right ) \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {1-x^4} \left (1+\frac {a^2}{b^2}-x^4\right )} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}} \\ & = \frac {a \left (8 a^2-37 b^2\right ) E\left (\left .\frac {1}{2} \arctan (\tan (e+f x))\right |2\right ) \sqrt [4]{\sec ^2(e+f x)}}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}-\frac {\left (5 b^3 \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {x^2}{a^2+b^2-b^2 x^4} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {\left (5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {a^2+b^2}-b x^2\right ) \sqrt {1-x^4}} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {\left (5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {a^2+b^2}+b x^2\right ) \sqrt {1-x^4}} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}} \\ & = \frac {a \left (8 a^2-37 b^2\right ) E\left (\left .\frac {1}{2} \arctan (\tan (e+f x))\right |2\right ) \sqrt [4]{\sec ^2(e+f x)}}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))}-\frac {\left (5 b^2 \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a^2+b^2}-b x^2} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {\left (5 b^2 \left (7 a^2-2 b^2\right ) \sqrt [4]{\sec ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a^2+b^2}+b x^2} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}+\frac {\left (5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+x^2} \left (\sqrt {a^2+b^2}-b x^2\right )} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {\left (5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+x^2} \left (\sqrt {a^2+b^2}+b x^2\right )} \, dx,x,\sqrt [4]{\sec ^2(e+f x)}\right )}{8 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}} \\ & = \frac {5 b^{3/2} \left (7 a^2-2 b^2\right ) \arctan \left (\frac {\sqrt {b} \sqrt [4]{\sec ^2(e+f x)}}{\sqrt [4]{a^2+b^2}}\right ) \sqrt [4]{\sec ^2(e+f x)}}{8 \left (a^2+b^2\right )^{13/4} f \sqrt {d \sec (e+f x)}}-\frac {5 b^{3/2} \left (7 a^2-2 b^2\right ) \text {arctanh}\left (\frac {\sqrt {b} \sqrt [4]{\sec ^2(e+f x)}}{\sqrt [4]{a^2+b^2}}\right ) \sqrt [4]{\sec ^2(e+f x)}}{8 \left (a^2+b^2\right )^{13/4} f \sqrt {d \sec (e+f x)}}+\frac {a \left (8 a^2-37 b^2\right ) E\left (\left .\frac {1}{2} \arctan (\tan (e+f x))\right |2\right ) \sqrt [4]{\sec ^2(e+f x)}}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {a \left (8 a^2-37 b^2\right ) \tan (e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)}}-\frac {5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \operatorname {EllipticPi}\left (-\frac {b}{\sqrt {a^2+b^2}},\arcsin \left (\sqrt [4]{\sec ^2(e+f x)}\right ),-1\right ) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}}{8 \left (a^2+b^2\right )^{7/2} f \sqrt {d \sec (e+f x)}}+\frac {5 a b \left (7 a^2-2 b^2\right ) \cot (e+f x) \operatorname {EllipticPi}\left (\frac {b}{\sqrt {a^2+b^2}},\arcsin \left (\sqrt [4]{\sec ^2(e+f x)}\right ),-1\right ) \sqrt [4]{\sec ^2(e+f x)} \sqrt {-\tan ^2(e+f x)}}{8 \left (a^2+b^2\right )^{7/2} f \sqrt {d \sec (e+f x)}}+\frac {b \left (4 a^2-5 b^2\right ) \sec ^2(e+f x)}{2 \left (a^2+b^2\right )^2 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {2 (b+a \tan (e+f x))}{\left (a^2+b^2\right ) f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^2}+\frac {a b \left (8 a^2-37 b^2\right ) \sec ^2(e+f x)}{4 \left (a^2+b^2\right )^3 f \sqrt {d \sec (e+f x)} (a+b \tan (e+f x))} \\ \end{align*}
Result contains complex when optimal does not.
Time = 39.23 (sec) , antiderivative size = 14652, normalized size of antiderivative = 22.07 \[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\text {Result too large to show} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 78531 vs. \(2 (611 ) = 1222\).
Time = 15.80 (sec) , antiderivative size = 78532, normalized size of antiderivative = 118.27
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Timed out. \[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\text {Timed out} \]
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\[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\int \frac {1}{\sqrt {d \sec {\left (e + f x \right )}} \left (a + b \tan {\left (e + f x \right )}\right )^{3}}\, dx \]
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\[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\int { \frac {1}{\sqrt {d \sec \left (f x + e\right )} {\left (b \tan \left (f x + e\right ) + a\right )}^{3}} \,d x } \]
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\[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\int { \frac {1}{\sqrt {d \sec \left (f x + e\right )} {\left (b \tan \left (f x + e\right ) + a\right )}^{3}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {d \sec (e+f x)} (a+b \tan (e+f x))^3} \, dx=\int \frac {1}{\sqrt {\frac {d}{\cos \left (e+f\,x\right )}}\,{\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^3} \,d x \]
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